(5x+6)(2x^2-9x+7)=0

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Solution for (5x+6)(2x^2-9x+7)=0 equation:


Simplifying
(5x + 6)(2x2 + -9x + 7) = 0

Reorder the terms:
(6 + 5x)(2x2 + -9x + 7) = 0

Reorder the terms:
(6 + 5x)(7 + -9x + 2x2) = 0

Multiply (6 + 5x) * (7 + -9x + 2x2)
(6(7 + -9x + 2x2) + 5x * (7 + -9x + 2x2)) = 0
((7 * 6 + -9x * 6 + 2x2 * 6) + 5x * (7 + -9x + 2x2)) = 0
((42 + -54x + 12x2) + 5x * (7 + -9x + 2x2)) = 0
(42 + -54x + 12x2 + (7 * 5x + -9x * 5x + 2x2 * 5x)) = 0
(42 + -54x + 12x2 + (35x + -45x2 + 10x3)) = 0

Reorder the terms:
(42 + -54x + 35x + 12x2 + -45x2 + 10x3) = 0

Combine like terms: -54x + 35x = -19x
(42 + -19x + 12x2 + -45x2 + 10x3) = 0

Combine like terms: 12x2 + -45x2 = -33x2
(42 + -19x + -33x2 + 10x3) = 0

Solving
42 + -19x + -33x2 + 10x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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